Calculate sum of 1+(1/2!)+…+(1/n!) n number in C language

Question

Like the title say, how I calculate the sum of n number of the form: 1+(1/2!)+⋯(1/n!)? I already got the code for the harmonic series:

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Answer 1

If you're just looking for computing the first n factorials, I would suggest just computing them recursively, e.g.

factorial[0] = 1;
for (i = 1; i < n; i++) factorial[i] = factorial[i-1] * i;

However, unless you store them as floating point numbers, the large factorials are going to overflow really quickly.