PHP Read CSV and filter by date

Question

I have the following CSV

Date,Event,Description
24/01/2010,Football,Football practice for all Years.
24/01/2010,Cricket,Cricket Practice for all Years.
25/01/201         


        

Answer 1

As an alternative to fgetcsv and iterating, you could also use a Regular Expressions to get the appropriate lines, e.g. for

Date,Event,Description
24/01/2010,Football,Football practice for all Years.
24/01/2010,Cricket,Cricket Practice for all Years.
25/01/2010,Piano Lessons,Paino lessons for Year 10.
26/01/2010,Piano Lessons II.

use

date_default_timezone_set('Europe/Berlin');    
$pattern = sprintf('#%s.*|%s.*#', date('d/m/Y'), 
                                  date('d/m/Y', strtotime("+1 day")) );
$file = file_get_contents('filename.csv');
preg_match_all($pattern, $file, $matches);
var_dump($matches);

and receive

array(1) {
  [0]=>
  array(3) {
    [0]=> string(53) "24/01/2010,Football,Football practice for all Years."
    [1]=> string(51) "24/01/2010,Cricket,Cricket Practice for all Years."
    [2]=> string(52) "25/01/2010,Piano Lessons,Paino lessons for Year 10."
  }
}

Haven't benchmarked this though. Depending on the size of your CSV file, this could get memory intensive, due to file_get_contents loading the entire file into a variable.

---

Another alternative with SplFileObject:

$today    = date('d/m/Y');
$tomorrow = date('d/m/Y', strtotime("+1 day"));
$file = new SplFileObject("csvfile.csv");
$file->setFlags(SplFileObject::READ_CSV);
foreach ($file as $row) {
    list($date, $event, $description) = $row;
    if($date === $today || $date === $tomorrow) {
        echo "Come visit us at $date for $description";
    }
}