Arithmetic overflow: Using operator '*' on a 4 byte value then casting the result to a 8 byte value

Question

I am trying to write a program to solve a quadratic equation whose coefficients\' values do not exceed 100 by absolute value and it is guaranteed that if any roots exist, they a

Answer 1

The way to fix this is to static_cast because long long is 8 bytes and it is large enough to hold the information in the event of an overflow. An overflow occurs when you try to hold a number when you do not have enough bits to do so and as a result some of them get chopped off.

Here is an example without the warning:

std::cout << "Two roots: " << (-b - std::sqrt(d)) / (2 * static_cast(a)) << " "
          << (-b + std::sqrt(d)) / (2 * static_cast(a));