split semicolon delimiter SQL to rows [duplicate]

Answer 1

Option 1 with a UDF

Declare @YourTable table (ID int, Value varchar(max))
Insert Into @YourTable values
(1,'A&B;C;D;E, F')

Select A.ID
      ,B.*
 From @YourTable A
 Cross Apply [dbo].[udf-Str-Parse-8K](A.Value,';') B

Option 2 without a UDF

Select A.ID
      ,B.*
 From @YourTable A
 Cross Apply (
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('' + replace((Select replace(A.Value,';','§§Split§§') as [*] For XML Path('')),'§§Split§§','')+'' as xml).query('.')) as A 
                Cross Apply x.nodes('x') AS B(i)
              ) B

Both Return

ID  RetSeq  RetVal
1   1       A&B
1   2       C
1   3       D
1   4       E, F

This UDF is XML Safe and VERY fast

CREATE FUNCTION [dbo].[udf-Str-Parse-8K] (@String varchar(max),@Delimiter varchar(25))
Returns Table 
As
Return (  
    with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
           cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 a,cte1 b,cte1 c,cte1 d) A ),
           cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter)) = @Delimiter),
           cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter,@String,s.N),0)-S.N,8000) From cte3 S)

    Select RetSeq = Row_Number() over (Order By A.N)
          ,RetVal = LTrim(RTrim(Substring(@String, A.N, A.L)))
    From   cte4 A
);
--Orginal Source http://www.sqlservercentral.com/articles/Tally+Table/72993/
--Much faster than str-Parse, but limited to 8K
--Select * from [dbo].[udf-Str-Parse-8K]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse-8K]('John||Cappelletti||was||here','||')