Awk print matched column if exists else print not found

Question

My text file looks like below

date=\"2017-10-10\" ip=192.168.1.1:22 inbound=100 outbound=100
date=\"2017-10-10\" ip=192.168.1.1:22 inbound=100
date=\"2017-10-10         


        

Answer 1

Using GNU awk

awk '{print match($0,/inbound=([0-9]+)/,a)?a[1]:0}' file

In perl

perl -lne 'print /inbound=(\d+)/?$1:0' file

In sed

sed 's/.*inbound=\([0-9]\+\).*/\1/;t;s/.*/0/' file