pivot html table using php

Question

I have this php code:

$query_production = \"SELECT uploadedby as name, sum(points) as points,
date_format(uploaddate,\'%Y-%m-%d\') as date FROM imsexport 
WHERE          


        

Answer 1

This will get you most of the way there; what I've left to you is how to get the left offset correct (or the date/points column alignment; hint, you'll need to keep the date with the name/points pair and know it's offset in $cols).

Obviously you're dealing with rows out of a database, so it'll be a little bit different.

See the codepad demo link below the code.

 $date, 'points' => $points));
}

$cols = array_unique($cols);

print_r($pivot);

echo implode('|', $cols);

echo PHP_EOL;

foreach ($pivot as $name => $row) {
    while ($entry = array_shift($row)) {
        echo str_pad($name, 7, ' ') . str_pad($entry['points'], 3, ' ', STR_PAD_LEFT) . '|';
    }

    echo PHP_EOL;
}

?>

http://codepad.org/WqqpKwn3