Template specialization within class definition

Question

I wonder whether it is possible to put the whole code of such a class inside the class (kind of as in Java). I\'m doing this for some piece of code, instead of having to search

Answer 1

Yes.

It is completely possible though the specialization must be done in other template.

#include 

template  class A {
public:
    A() {
        std::cout<<"Generic"< class A
{
public:
    A() { std::cout << "Bool specialization" << endl; }
};

int main(int argc, char** argv) {
    A a;
    A b;
}