how to convert row to column in SQL

Question

Can somebody help me with this SQL Query.

In the following table, RESPONSES counts how many times SEGMENT has responded on CHECKED date.

CREATE TABLE #         


        

Answer 1

Please see this on StackOverFlow: If using SQL Server 2005 or greater...

DECLARE  @test TABLE
(
    ID INT, 
    SEGMENT CHAR(1),
    RESPONSES INT,
    CHECKED SMALLDATETIME
)

INSERT INTO @test VALUES (1,'A',0,'2009-05-01')
INSERT INTO @test VALUES (2,'B',1,'2009-05-01')
INSERT INTO @test VALUES (3,'C',0,'2009-05-01')
INSERT INTO @test VALUES (4,'A',0,'2009-05-02')
INSERT INTO @test VALUES (5,'B',2,'2009-05-02')
INSERT INTO @test VALUES (6,'C',1,'2009-05-02')
INSERT INTO @test VALUES (7,'A',1,'2009-05-03')
INSERT INTO @test VALUES (8,'B',0,'2009-05-03')
INSERT INTO @test VALUES (9,'C',2,'2009-05-03')


SELECT * FROM 
(    
    SELECT  SEGMENT,
            RESPONSES,
            CHECKED
    FROM @test
) AS subquery 
PIVOT 
(
    SUM(responses) 
    FOR SEGMENT IN ([a],[b],[c])
) AS pivotquery

---

Dynamic SQL Example

CREATE TABLE ##test
(
    ID INT, 
    SEGMENT CHAR(1),
    RESPONSES INT,
    CHECKED SMALLDATETIME
)

INSERT INTO ##test VALUES (1,'A',0,'2009-05-01')
INSERT INTO ##test VALUES (2,'B',1,'2009-05-01')
INSERT INTO ##test VALUES (3,'C',0,'2009-05-01')
INSERT INTO ##test VALUES (4,'A',0,'2009-05-02')
INSERT INTO ##test VALUES (5,'B',2,'2009-05-02')
INSERT INTO ##test VALUES (6,'C',1,'2009-05-02')
INSERT INTO ##test VALUES (7,'A',1,'2009-05-03')
INSERT INTO ##test VALUES (8,'B',0,'2009-05-03')
INSERT INTO ##test VALUES (9,'C',2,'2009-05-03')

DECLARE @SQLa VARCHAR(255),
        @SQLb VARCHAR(255),
        @SQLc VARCHAR(255)

SET @SQLa =
'SELECT * FROM 
(    
    SELECT  SEGMENT,
            RESPONSES,
            CHECKED
    FROM ##test
) AS subquery 
PIVOT 
(
    SUM(responses) 
    FOR SEGMENT IN ('

SET @SQLc = ')
) AS pivotquery'

SELECT @sqlB = STUFF(
(
    SELECT ',[' + SEGMENT + ']'
    FROM ##test WITH (NOLOCK)
    GROUP BY SEGMENT
    FOR XML PATH('')
),1, 1, '')

EXECUTE (@SQLa + @SQLb + @SQLc)

DROP TABLE ##test