Pyspark : Change nested column datatype

后端 未结 2 1407
广开言路
广开言路 2021-01-23 18:52

How can we change the datatype of a nested column in Pyspark? For rxample, how can I change the data type of value from string to int?

Reference:how to change a Datafram

2条回答
  •  挽巷
    挽巷 (楼主)
    2021-01-23 19:33

    You can read the json data using

    from pyspark import SQLContext
    
    sqlContext = SQLContext(sc)
    data_df = sqlContext.read.json("data.json", multiLine = True)
    
    data_df.printSchema()
    

    output

    root
     |-- x: long (nullable = true)
     |-- y: struct (nullable = true)
     |    |-- p: struct (nullable = true)
     |    |    |-- name: string (nullable = true)
     |    |    |-- value: long (nullable = true)
     |    |-- q: struct (nullable = true)
     |    |    |-- name: string (nullable = true)
     |    |    |-- value: long (nullable = true)
    

    Now you can access the data from y column as

    data_df.select("y.p.name")
    data_df.select("y.p.value")
    

    output

    abc, 10
    

    Ok, the solution is to add a new nested column with correct schema and drop the column with wrong schema

    from pyspark.sql.functions import *
    from pyspark.sql import Row
    
    df3 = spark.read.json("data.json", multiLine = True)
    
    # create correct schema from old 
    c = df3.schema['y'].jsonValue()
    c['name'] = 'z'
    c['type']['fields'][0]['type']['fields'][1]['type'] = 'long'
    c['type']['fields'][1]['type']['fields'][1]['type'] = 'long'
    
    y_schema = StructType.fromJson(c['type'])
    
    # define a udf to populate the new column. Row are immuatable so you 
    # have to build it from start.
    
    def foo(row):
        d = Row.asDict(row)
        y = {}
        y["p"] = {}
        y["p"]["name"] = d["p"]["name"]
        y["p"]["value"] = int(d["p"]["value"])
        y["q"] = {}
        y["q"]["name"] = d["q"]["name"]
        y["q"]["value"] = int(d["p"]["value"])
    
        return(y)
    map_foo = udf(foo, y_schema)
    
    # add the column
    df3_new  = df3.withColumn("z", map_foo("y"))
    
    # delete the column
    df4 = df3_new.drop("y")
    
    
    df4.printSchema()
    

    output

    root
     |-- x: long (nullable = true)
     |-- z: struct (nullable = true)
     |    |-- p: struct (nullable = true)
     |    |    |-- name: string (nullable = true)
     |    |    |-- value: long (nullable = true)
     |    |-- q: struct (nullable = true)
     |    |    |-- name: string (nullable = true)
     |    |    |-- value: long (nullable = true)
    
    
    df4.show()
    

    output

    +---+-------------------+
    |  x|                  z|
    +---+-------------------+
    | 12|[[abc,10],[pqr,10]]|
    +---+-------------------+
    

提交回复
热议问题