Open CSV file and writing each row to new, dynamically named CSV file

Question

I have a csv file with, say, 50 rows of data, and I would like to split it into separate csv files for each row, which includes first row (header) and the the relevant row.

Answer 1

Here is a solution with pandas. Assume the content of csv as follows:

Name, Age, Gender
John, 20, Male
Jack, 22, Male
Jill, 18, Female

And my code is as follows:

import pandas as pd
df = pd.read_csv("mock_data.csv")

for index, row in df.iterrows():
    file_name = row['Name']+".csv"  #Change the column name accordingly
    pd.DataFrame(row).T.to_csv(file_name, index=None)

This will create filenames based on the values of the column "Name" (i.e. Jack, John and Jill) to produce three files John.csv, Jack.csv and Jill.csv. Content of John.csv is as follows:

Name    | Age   |  Gender |
---------------------------
John    | 20    |  Male   |

Content of Jack.csv is as follows:

Name    | Age   |  Gender |
---------------------------
Jack    | 22    |  Male   |

Content of Jill.csv is as follows:

Name    | Age   |  Gender |
---------------------------
Jill    | 20    |  Female   |

P.S: If you don't want the header, just add header = None when calling .to_csv() function. For example:

pd.DataFrame(row).T.to_csv(file_name, index=None, Header=None)