unexpected end of regular expression

Question

I want to get only the file name with extension from the path:

C:\\\\Users\\\\anandada\\\\workspace\\\\MyTestProject\\\\         


        

Answer 1

It is because you don't use a raw string. The double backslash is interpreted as an escape for the closing square bracket. You need to write:

fileName = re.match(r"[^\\]*.c$", fileName)

with the raw string format \\ is seen as a literal backslash as expected.