String concatenation in Bash script

Question

I am writing this Bash script:

count=0   
result

for d in `ls -1 $IMAGE_DIR | egrep \"jpg$\"`
do

    if (( (count % 4) == 0 )); then
                result=\"a         


        

Answer 1

Something like this?

count=0   

find $IMAGE_DIR -name "*.jpg" |
while read f; do
        if (( (count % 4) == 0 )); then
                result="abc $f"

                if (( count > 0 )); then
                        echo $result
                fi

        else
                result="$result $d"
        fi

        (( count++ ))
done