How Can I Make Oracle Query Sort Order Dynamic?

Question

I have a Oracle procedure inside a package like this

PROCEDURE getEmployee
(
  pinLanguage               IN    VARCHAR2,
  pinPage                   IN    NUMBER         


        

Answer 1

Try this one:

WHERE ...
ORDER BY 
   CASE pinSortColumn 
      WHEN 'FullName' THEN FULL_NAME 
      WHEN 'DateOfBirth' THEN DATE_OF_BIRTH
      WHEN 'Gender' THEN GEN_TR.GENDER   
   END;

However, I don't think you can use ASC, DESC is this way. You to create a dynamic query. For an OPEN ... FOR ... statement it is trivial:

sqlstr := 'SELECT * FROM (
      SELECT EMPLOYEE_ID, USERNAME, FULL_NAME, DATE_OF_BIRTH, EMP.GENDER_ID, GEN_TR.GENDER, EMP.WORK_TYPE_ID, WT_TR.WORK_TYPE, SALARY, EMAIL, PROFILE_IMAGE,
      ROW_NUMBER() OVER (ORDER BY EMPLOYEE_ID ASC) RN

      FROM EMPLOYEES EMP
      INNER JOIN GENDERS GEN ON EMP.GENDER_ID = GEN.GENDER_ID
      LEFT JOIN GENDERS_MLD GEN_TR ON GEN.GENDER_ID = GEN_TR.GENDER_ID AND GEN_TR.LANGUAGE = :pinLanguage
      INNER JOIN WORK_TYPES WT ON EMP.WORK_TYPE_ID = WT.WORK_TYPE_ID
      LEFT JOIN WORK_TYPES_MLD WT_TR ON WT.WORK_TYPE_ID = WT_TR.WORK_TYPE_ID AND WT_TR.LANGUAGE = :pinLanguage
    )
    WHERE RN BETWEEN (((:pinPage - 1) * :pinPageSize) + 1) AND (:pinPage * :pinPageSize) 
    ORDER BY '

CASE pinSortColumn 
   WHEN 'FullName' THEN sqlstr := sqlstr || 'FULL_NAME ';
   WHEN 'DateOfBirth' THEN sqlstr := sqlstr || 'DATE_OF_BIRTH ';
   WHEN 'Gender' THEN sqlstr := sqlstr || 'GEN_TR.GENDER ';
END CASE;   
sqlstr := sqlstr || pinSortOrder;

OPEN poutEmployeeCursor FOR sqlstr USING pinLanguage, pinLanguage, pinPage, pinPageSize, pinPage, pinPageSize;

Not in case you run Oracle 12c or newer you can use the Row Limiting Clause instead of dealing with row number.