How fget works?

Question

I am using gcc (Ubuntu 4.8.2-19ubuntu1) 4.8.2
I am writing a very simple script to take string as input and print the same with the some custom message. Fi

Answer 1

With your first call to scanf you allow the user to input an integer for the number of loops. They do so, and use a carriage return to signal the end of input. At this point scanf reads the integer, but leaves the end-of-line (\n) in the stream..

So when you call fgets, fgets gets from the stream until it reaches the first newline -- in you code, on the first loop, this is the very first character it encounters.

If you discard the newline before calling fgets, you should get your desired results. You can do this, for example by changing your first three lines to:

    int T;
    char newline;
    scanf("%d%c",&T, &newline);

Although there are probably stylistically superior ways of doing this.