How to create a strong typedef in C++(11) without an external library?

Question

So, I know you can alias types with the following:
typedef int *intPtr
But the C++ compiler can\'t differentiate between them:

typedef int         


        

Answer 1

A typedef or using statement will not introduce a new type.

To get a new type you need to define one:

struct foo { int x; };
struct bar { int x; };

int main()
{
    //typedef int foo;
    //typedef int bar;
    foo x{5};
    bar y{7};
    int z = x + y;  // now doesn't compile, wants an operator+() defined  
    return 0;
}

In the above example we take advantage of aggregate initialization to allow for the use of the structs in this way.