This is what I have so far, but it\'s not working in the test file. Basically skips to the else if(cnode == preposition)
void LinkedList::Delete(Nod
Three cases of delete in a singly linked-list:
delete the first node
void delete_first()
{
node *temp=new node;
temp=head;
head=head->next;
delete temp;
}
delete the last node
void delete_last()
{
node *current = new node;
node *previous = new node;
current=head;
while(current->next != NULL)
{
previous = current;
current = current->next;
}
tail = previous; // if you have a Node* tail member in your LinkedList
previous->next = NULL;
delete current;
}
delete at a particular position (your case)
void LinkedList::delete_position(int pos)
{
node *current=new node;
node *previous=new node;
current=head;
for(int i=1; i < pos; i++) //or i = 0; i < pos-1
{
previous=current;
current=current->next;
}
previous->next=current->next;
delete current;
}
^^ from codementor ^^
However if your function signature intends delete_node(Node* nodeToDelete)
[PrePosition is not a good name in this case] and you want delete the node passed to the function without knowing its position in the list we can modify delete_position() like so:
void LinkedList::delete_node(Node* nodeToDelete)
{
node *current= head;
node *previous= nullptr;
if (head == nodeToDelete){
head = nodeToDelete->next;
delete nodeToDelete;
return
}//else
while(current != nodeToDelete)
{
previous = current;
current = current->next
}
previous->next = current->next;
delete nodeToDelete;
}
Also in your original code, if it's skipping the line you mentioned, pnode is always null when cnode has a non-null value in it.