How to find the size of a file and assign it to a variable in UNIX

Question

I am writing a UNIX script that reads the size of a text file and if the file is of some size it should print the text file. If it is not an else loop executes and the process c

Answer 1

Assign your file size in a variable and then check equality with -eq

size=`ls -l ${filepath}/{filename}.lst| awk '{print $5}'`
if [ $size  -eq 461 ]
then
   echo "MATCHED"
else
  echo "NOT MATCHED"
fi