How to find the size of a file and assign it to a variable in UNIX

Question

I am writing a UNIX script that reads the size of a text file and if the file is of some size it should print the text file. If it is not an else loop executes and the process c

Answer 1

I wouldn't recomment stat which is not portable not being specified by POSIX.

Here is a safer way to get the file size in a variable.

size=$(ls -dnL -- "${filepath}/{filename}.lst" | awk '{print $5;exit}')