Manipulate date in UNIX

Question

I want to find a way to list all the dates of the current week in UNIX. For example if today is 17-07-2018 then how to get dates 16-07, 18-07, 19-07 and so on for the whole week

Answer 1

Well, now I think it requires GNU!date or some actual programming language. Perl, for instance.

#!/usr/bin/perl

use strict;
use POSIX;

my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst);
my ($w,$ts);

($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = gmtime();

$ENV{'TZ'}='GMT';
POSIX::tzset ();

$ts = POSIX::mktime (0, 0, 0, $mday, $mon, $year);
$ts = $ts - 24*60*60 * $wday;

for ($w= 1; $w<=7; ++$w) {
    ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) =
        gmtime($ts + (24*60*60)*$w);
    printf ("%04d-%02d-%02dn", $year+1900, $mon+1, $mday);
}

If you save it as $HOME/bin/weekdays.pl then you can use it in your scripts:

set $(perl ~/bin/weekdays.pl)
echo "Monday is $1"