Automatic destruction of object even after calling destructor explicitly

Question

The following program :

#include 
using namespace std;

class Test
{
public:
    Test() { cout << \"Constructor is executed\\n\"; }
    ~Te         


        

Answer 1

the scope of t is the main function. Its created on the stack and will be destroyed at the end of the function.

That's how its supposed to work and when you call the destructor on it early, you don't change that.

You don't need to call the destructor and in this case doing so leads to it being called twice.

if you'd used

Test* t = new Test();

the destructor would not have been automatically called at the end of main.