Why the array size is 1 [duplicate]

Answer 1

As a parameter int iArray[] is equivalent to int *iArray.

So when you do

int arrayL=sizeof(*iArray)/sizeof(int);

You are actually doing

int arrayL=sizeof(int)/sizeof(int);

Which is the same size.

You need to add a parameter with which you pass the size information.

int inArrayInt(int iVal, int iArray[], size_t numel){
  ...
  for(i=0;i