N.B: Directly connected to a problem I had a few years ago, but I\'d like to resolve the first issue there which wasn\'t otherwise part of the question, so please don\'t fla
So, what you are really trying to do is count the instances of $N
in your string, where N
is a decimal digit. To do this, just look in the string for instances of $
using std::string::find
, and then check the next character to see if it is a digit.
std::string::size_type pos = 0;
while ((pos = input.find('$', pos)) != std::string::npos) {
if (pos + 1 == input.size()) {
break; // The last character of the string is a '$'
}
if (std::isdigit(input[pos + 1])) {
width += 2;
}
++pos; // Start next search from the next char
}
In order to use std::isdigit
, you need to first:
#include