Converting a set of strings to a byte[] array

Question

I am tring to convert a set of strings to a byte[] array. At first, I do something like this to convert a byte array to a string:

public String convertByte(byte[         


        

Answer 1

This should work:

byte[] bytes = "Hello World".getBytes("UTF-8");
String hello = new String(bytes, "UTF-8");

The above example uses the UTF-8 encoding and just serves as an example. Use the character encoding you expect in your message input. (This 'answer' wasn't an answer to the question...)

Edit

So we need a conversion from byte[] to String and back to byte[]. me123 added delimiters between the (and in front of) the values. As others already explained, 1. the regexp for the split has to be " \\* " and 2. the magic method is Byte.parseByte(st[i])

Here is an alternative without using a delimiter but a fixes width for the byte entries. The StringToByte converter shows a pretty fast solution just based on the strings char array.

public static String convertByte(byte[] msg) {
    StringBuilder sb = new StringBuilder();
    for (byte b:msg) {
        sb.append(String.format("%02x", b));
    }
    return sb.toString();
}

public static byte[] convertStr(String ln)
{
    System.out.println(ln);
    char[] chars = ln.toCharArray();
    byte[] result = new byte[ln.length()/2];
    for (int i = 0;i < result.length; i++) {
        result[i] = (byte) hexToInt(chars[2*i], chars[2*i+1]);
    }

    return result;
}

private static int hexToInt(char c1, char c2) { 
    return ((c1 <= '9' ? c1 - '0':c1 - 'a'+10) << 4) 
           + (c2 <= '9' ? c2 - '0':c2 - 'a'+10);
}