I have an image which is read as a uint8 array with the shape (512,512,3)
.
Now I would like to convert this array to a uint8 array of shape (512,512,1)
Here's one based on views
-
# https://stackoverflow.com/a/45313353/ @Divakar
def view1D(a, b): # a, b are arrays
# This function gets 1D view into 2D input arrays
a = np.ascontiguousarray(a)
b = np.ascontiguousarray(b)
void_dt = np.dtype((np.void, a.dtype.itemsize * a.shape[-1]))
return a.view(void_dt).ravel(), b.view(void_dt).ravel()
def img2label(a, maps):
# Get one-dimension reduced view into input image and map arrays.
# We need to reshape image to 2D, then feed it to view1D to get 1D
# outputs and then reshape 1D image to 2D
A,B = view1D(a.reshape(-1,a.shape[-1]),maps)
A = A.reshape(a.shape[:2])
# Trace back positions of A in B using searchsorted. This gives us
# original order, which is the final output.
sidx = B.argsort()
return sidx[np.searchsorted(B,A,sorter=sidx)]
Given that your labels start from 1
, you might want to add 1
to the output.
Sample run -
In [100]: # Mapping array
...: maps = np.array([[0, 0, 0],[0, 0, 255],\
...: [255, 0, 0],[150, 30, 150]],dtype=np.uint8)
...:
...: # Setup random image array
...: idx = np.array([[0,2,1,3],[1,3,2,0]])
...: img = maps[idx]
In [101]: img2label(img, maps) # should retrieve back idx
Out[101]:
array([[0, 2, 1, 3],
[1, 3, 2, 0]])