Why print() is printing my String as an optional?

Question

I have a dictionary and I want to use some of its values as a key for another dictionary:

let key: String = String(dictionary[\"anotherKey\"])

Answer 1

You can also avoid force unwrapping by using default for the case that there is no such key in dictionary

var dictionary = ["anotherkey" : 42]

let key: String = 
String(dictionary["anotherkey", default: 0])
print(key)