Bash: pass variable as a single parameter / shell quote parameter

Question

I\'m writing a bash script which has to pass a variable to another program:

./program $variable

The problem is, it is absolutely necessary for

Answer 1

This is almost certainly a problem in the way you are reading the variable in your program.
For instance suppose this is your script (just one line for testing):

echo "$1"

Let's call it echo.sh. If you run echo.sh "test best", you will get test best.

But if your program says

echo $1

you might get behaviour like what you're seeing.