Bash: pass variable as a single parameter / shell quote parameter

Question

I\'m writing a bash script which has to pass a variable to another program:

./program $variable

The problem is, it is absolutely necessary for

Answer 1

Have a look on http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_03_04.html .

The problem is that the expansion of variables is done before of the command line parameters hence your behavior.

You might work it arround with setting IFS to something weird as

IFS='###' V='foo bar baz'; ./program $V