Bash: pass variable as a single parameter / shell quote parameter

Question

I\'m writing a bash script which has to pass a variable to another program:

./program $variable

The problem is, it is absolutely necessary for

Answer 1

When you call your script pass the arguments within quotes.

Example script:

#!/bin/bash
for arg in "$@"; do
 echo "arg: $1";
 shift;
done

When you call it with:

./program "parameter with multiple words" parameter2 parameter3 "another parameter"

The output should be:

arg: parameter with multiple words
arg: parameter2
arg: parameter3
arg: another parameter