How to use PHP variable in Javascript?

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遇见更好的自我
遇见更好的自我 2021-01-22 23:18

I know you can\'t directly use PHP variables inside javascript code, but is there a way around it? I need to use these parameter\'s in javascript:

username: \'&l         


        
5条回答
  •  一整个雨季
    2021-01-22 23:38

    Resource id #4 means u have just not complete the mysql query

    mysql_query returns Resource id

    u have to fetch the data using while ($row=mysql_fetch_array()) and then use

    written here

    For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_query() returns a resource on success, or FALSE on error.

    For other type of SQL statements, INSERT, UPDATE, DELETE, DROP, etc, mysql_query() returns TRUE on success or FALSE on error.

    UPDATE

    don't use mysql_real_escape string for GET data..instead use (int)$_GET['id']

    see here

    If no connection is found or established, an E_WARNING level error is generated

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