convert image to byte literal in python

Question

I\'m trying to store an image as text, so that I can do something like this example of a transparent icon for a Tk gui:

import tempfile

# byte literal code for          


        

Answer 1

Well I did figure out you can do it this way:

import tempfile, base64, io

# byte literal code for a transparent icon, I think
ICON = (b'\x00\x00\x01\x00\x01\x00\x10\x10\x00\x00\x01\x00\x08\x00h\x05\x00\x00'
        b'\x16\x00\x00\x00(\x00\x00\x00\x10\x00\x00\x00 \x00\x00\x00\x01\x00'
        b'\x08\x00\x00\x00\x00\x00@\x05\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00'
        b'\x00\x01\x00\x00\x00\x01') + b'\x00'*1282 + b'\xff'*64

# makes a temp file for the transparent icon and saves it
_, ICON_PATH = tempfile.mkstemp()
with open(ICON_PATH, 'wb') as icon_file:
    icon_file.write(ICON)

with open(ICON_PATH, 'rb') as imgFile:
    a = imgFile.read()

b = base64.b64encode(a)

print b # output does not match what ICON equals above

with open('test.png','wb') as writeFile:
    writeFile.write(b.decode('base64'))

but I still want to know how to get the same format as 'ICON = (...' at the top