Can UnaryOperator be a member function when std::transform is called

Question

Based on std::transform

template < class InputIterator, class OutputIterator, class UnaryOperator >
  OutputIterator transform ( InputIterator first1, Inpu         


        

Answer 1

It is pretty easy to do if you wrap the call in lambda:

#include 
#include 

class C {
public:
  int op() const { return 1; }
};

class D {
  int op() { return 1; }
  void f() {
    std::vector xs;
    std::vector ys;
    std::transform(xs.begin(), xs.end(), ys.begin(),
      [](const C& x) { return x.op(); });
    std::transform(xs.begin(), xs.end(), ys.begin(),
      [this](const C& x) { return this->op(); });
  }
};