Can UnaryOperator be a member function when std::transform is called

Question

Based on std::transform

template < class InputIterator, class OutputIterator, class UnaryOperator >
  OutputIterator transform ( InputIterator first1, Inpu         


        

Answer 1

No (well, not directly). You need to use an adaptor, either old std::mem_fun (together with bind1st, IIRC) or std::bind/boost::bind.

std::transform(
    xs.begin(), xs.end(), ys.begin(),
    std::bind(&Class::member, &class_instance)
);