multiplication of double with integer precision

Question

I have a double of 3.4. However, when I multiply it with 100, it gives 339 instead of 340. It seems to be caused by the precision of double. How could I get around this?

Answer 1

You could use two integers and multiply the fractional part by multiplier / 10.

E.g

int d[2] = {3,4};
int n = (d[0] * 100) + (d[1] * 10);

If you really want all that precision either side of the decimal point. Really does depend on the application.