There are many threads on SO about interrupting reading the system.in but what I am looking for here is some kind of advice as to how to best code what I am trying to achieve.>
The simplest solution is to expose the underlying stream in the "reading" thread and close that stream from the timeout thread. This should interrupt the reading and raise an exception. Handle this exception and you should be able to proceed with your logic. The only gotcha is that you won't be able to re-use the same stream again. Unfortunately there is no easy way to deal with interruption of blocking system calls.
EDIT:
Following a completely different line of reasoning; given that we can't close the input stream just to interrupt it, the only way I can think of is to use the "programmatic user input" facilities offered by the Robot class. Here is an example which works out for me:
import java.awt.Robot;
import java.awt.event.KeyEvent;
import java.util.Scanner;
import java.util.concurrent.TimeUnit;
public class ConsoleTest {
/**
* @param args
*/
public static void main(String[] args) {
new TimeoutThread().start();
new ReaderThread().start();
}
}
class ReaderThread extends Thread {
@Override
public void run() {
System.out.print("Please enter your name: ");
try(Scanner in = new Scanner(System.in)) {
String name = in.nextLine();
if(name.trim().isEmpty()) {
name = "TEST"; // default user name
}
System.out.println("Name entered = " + name);
}
}
}
class TimeoutThread extends Thread {
@Override
public void run() {
try {
Thread.sleep(TimeUnit.SECONDS.toMillis(5));
Robot robot = new Robot();
robot.keyPress(KeyEvent.VK_ENTER);
robot.keyRelease(KeyEvent.VK_ENTER);
} catch(Exception e) {
e.printStackTrace();
}
}
}
The above code uses the logic that once that timeout has expired, we simulate a newline which will cause the "name" variable to be blank. Then we have a check which performs the necessary logic and sets the appropriate user name.
The gotcha about the above approach is that it:
ENTER
key-press will be registered for that window as opposed to your application window.Hope this helps you out. I'm really out of ideas now. :)