using django rest framework to return info by name

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栀梦
栀梦 2021-01-22 19:24

I am using Django rest framework and I create this class to return all the name of project

class cpuProjectsViewSet(viewsets.ViewSet):
  serializer_class = seri         


        
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  •  借酒劲吻你
    2021-01-22 19:39

    One does not use raw queries unless absolutely needed and even then, there isn't a need to manually connect to the database because you have easy access to a connection object. Overall, your retrieve method can be improved as follows:

    def retrieve(self, request, pk=None):
        queryset = CpuProject.objects.all()
        cpu = get_object_or_404(queryset, pk=pk)
        serializer = serializers.cpuProjectsSerializer(cpu)
        return Response(serializer.data)
    

    Much shorter and easier to read. But Even this is not really needed If you use a ModelViewset! Then the default retrieve method will take care of this for you. So your viewset reduces to

    class cpuProjectsViewset(viewsets.ModelViewSet):
        serializer_class =serializer = serializers.cpuProjectsSerializer
        queryset = CpuProject.objects.all()
    

    You don't need a retrieve method here!!

    But I see that you are trying to retrieve a particular CpuProject item by it's name (rather than using it's PK). For that you need to add a route

    from rest_framework.decorators import detail_route, list_route
    @detail_route(url_path='(?P[\w-]+)')
    def get_by_name(self, request, pk=None,slug=None):
    
        queryset = CpuProject.objects.all()
        cpu = get_object_or_404(queryset, name=slug)
        serializer = serializers.cpuProjectsSerializer(cpu)
        return Response(serializer.data)
    

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