javascript async await Submitting a form with onsubmit using Promise

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后悔当初
后悔当初 2021-01-22 17:26

I\'m having following code.



  
    

        
1条回答
  •  借酒劲吻你
    2021-01-22 17:59

    The return check_form() does not return false as you might think. Async functions always return an implicit Promise and therefore, your form is still submitted. The first alert shows up because up to that moment it is still synchronous. Everything after the sleep will be scheduled for a later time and the form submission will not wait for that.

    To resolve it you can call the function and then return false.

    function sleep(lf_ms) {
      return new Promise(resolve => setTimeout(resolve, lf_ms));
    }
    
    async function check_form() {
      console.log('Test 1');
      await sleep(1000);
      console.log('Test 2');
    }


    check the method call via link




    Edit to address your comment

    User input is checked in the function check_form. If the inputs are error-free, the function returns true. If there are errors, the function returns false. In the event of an error, the page that is stored in the attribute action of the tag form should not be called.

    You can't pause JavaScript like that, but you can use return false to stop the submission and then after your validation, submit the form via JavaScript.

    function sleep(lf_ms) {
      return new Promise(resolve => setTimeout(resolve, lf_ms));
    }
    
    async function check_form(form) {
      console.log('Test 1');
      await sleep(1000);
      console.log('Test 2');
    
      let city = document.getElementById('city').value;
      // Validation
      if (form !== undefined && city.trim() !== "") {
        // Validation succeeded, submit the form
        form.submit();
      }
    }


    check the method call via link



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