swap in doubly linked list

Question

I am trying to swap two nodes in a doubly linked list. Below is the part of program having swap function.

 int swap (int x, int y)
{
    struct node *temp = NU         


        

Answer 1

The code will fail if ptr1 == head (ptr1->prev == NULL) or ptr2 == head (ptr2->prev == NULL), because it ends up trying to use head->next, which doesn't exist. There also needs to be a check for the end of a list, if ptr1->next == NULL or ptr2->next == NULL, which can be handled using a local tail pointer. Using pointers to pointer to node can simplify the code. For example the pointer to next pointer to ptr1 could be &ptr1->prev->next or &head. The pointer to prev pointer to ptr2 could be &ptr2->next->prev or &tail (and set tail = ptr2).

Using pointers to pointer to node fixes the issue with swapping adjacent nodes. Also temp can be a pointer to node.

Example code using pointers to nodes (instead of counts) to swap:

typedef struct node NODE;
/* ... */
NODE * SwapNodes(NODE *head, NODE *ptr1, NODE *ptr2)
{
NODE **p1pn;            /* & ptr1->prev->next */
NODE **p1np;            /* & ptr1->next->prev */
NODE **p2pn;            /* & b->prev->next */
NODE **p2np;            /* & b->next->prev */
NODE *tail;             /* only used when x->next == NULL */
NODE *temp;             /* temp */
    if(head == NULL || ptr1 == NULL || ptr2 == NULL || ptr1 == ptr2)
        return head;
    if(head == ptr1)
        p1pn = &head;
    else
        p1pn = &ptr1->prev->next;
    if(head == ptr2)
        p2pn = &head;
    else
        p2pn = &ptr2->prev->next;
    if(ptr1->next == NULL){
        p1np = &tail;
        tail = ptr1;
    } else
        p1np = &ptr1->next->prev;
    if(ptr2->next == NULL){
        p2np = &tail;
        tail = ptr2;
    }else
        p2np = &ptr2->next->prev;
    *p1pn = ptr2;
    *p1np = ptr2;
    *p2pn = ptr1;
    *p2np = ptr1;
    temp = ptr1->prev;
    ptr1->prev = ptr2->prev;
    ptr2->prev = temp;
    temp = ptr1->next;
    ptr1->next = ptr2->next;
    ptr2->next = temp;
    return head;
}