In bash, is there a way to substitue or nest a variable within a variable? [duplicate]

Answer 1

Use the declare built-in along with indirect-variable expansion in bash. First define the elements of for the dynamic nature in an array as

#!/bin/bash

list=(one two)
unset count

for var in "${list[@]}"; do 
    declare var_${var}_string="string"$((++count))
done

and now access the created variables using indirect expansion

for var in "${list[@]}"; do 
    dymv="var_${var}_string"
    echo "${!dymv}"
done

and never use eval for this requirement. Could be dangerous because of unlikely code-injection possibility with a harmful command.