How to display filename from a column using Awk?

Question

I\'m trying to do a command which add to my file: Name of the current input file + Index of line where numbers of commas are less than 5 + numbers of commas across the line.

Answer 1

FILENAME is a string, not a number. Use %s:

awk -F"," '{ if(NF > 5) printf("Filename: %s  Index: %d Number of commas : %d\n",FILENAME,NR, NF-1); }' dsc* >> filename.csv

From the section of man awk that discusses printf:

  %d, %i  A decimal number (the integer part).

  %s      A character string.