I\'m going to boil this problem down to the simplest form:
Let\'s iterate from [0 .. 5.0] with a step of 0.05 and print out \'X\' for every 0.25 multipl
I'd solve this by simply not using floating point variables in that way:
for (int i = 0; i <= 500; i += 5) { double d = i / 100.0; // in case you need to use it. if ((i % 25) == 0) print 'X'; }
They're usually problematic enough that it's worth a little extra effort in avoiding them.