Accessing dictionary of dictionary in python

Question

Hi in my code there is a dictionary of dictionary.

nrec={\'bridge\': \'xapi1\', \'current_operations\': {}, \'uuid\': \'9ae5ca7d-e7d6-7a81-f619-d0ea33efb534\', \         


        

Answer 1

Your best bet to avoid exception is either try .. except, or use dictionary built-in methods.

my_dict = {'one': {'two': 'hello world!'}, 'four': 'Dummy!'}
try:
  my_name = my_dict['one']['two']
except:
  pass
  // instead of pass, you can also return something or do something else

try:
  my_dict['one']['two']
except Exception as e:
  my_name = 'default'
  return my_name, e  // returns a tuple which contains 'default' and error message


#or use has_key()

# this is for one-level nested dictionary
for id, items in my_dict.iteritems():
     if items.has_key('two'):
          //do something

# or simply this  --> eliminates dummy for loop
if my_dict['one'].has_key('two'):      // has_key returns True / False
      // do something

# or use in operator  (replace has_key)
if 'two' in my_dict['one'].keys():
     // do something


# or get method

my_dict['one'].get('two', 'Default')

Get is nice if that's all you need to avoid exception.