Regex for IBAN mask

Question

I am trying to extract this text \"NL dd ABNA ffffdffffdffffd\" from string:

IBAN NL 91ABNA0417463300
IBAN NL91ABNA0417164300
Iban: NL 69 ABNA 402032566

Answer 1

It's not what you want, but works.

IBAN has a strict format, so it's better to normalize it, and next just cut part, because everything will match regexp, as an example:

CODE

#!/usr/bin/python3
# -*- coding: utf-8 -*-

# I'm not sure, that alphabet is correct, A-Z, 0-9
alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"


def normalize(string):
    stage1 = "".join(IBAN.split()).upper()
    stage2 = ''
    for l in stage1:
        if l in alphabet:
            stage2 = stage2 + l

    return stage2.split('IBAN')[1]


if __name__ == '__main__':

    IBAN_LIST = ['IBAN NL 91ABNA0417463300', 'IBAN NL91ABNA0417164300', 'Iban: NL 69 ABNA 402032566']

    for IBAN in IBAN_LIST:
        IBAN_normalized = normalize(IBAN)
        print(IBAN_normalized[2:4], IBAN_normalized[8:])

OUTPUT

91 0417463300
91 0417164300
69 402032566

It's not a regexp, but should work faster, but if you know how to normalize better, please, help with it.

You can see source code here.