I see an example from a book that I read about java:
public class A{
public A(){
System.out.println(\"A\");
}
}
public class B extends A{
public
Java implicitly calls the no argument super constructor. But it may happen that the super class constructor has arguments or there are multiple super class constructors. In this case you would have to explicitly mention which super class constructor you want to call (the compiler leaves that up to you)