Is there a way to call an object's base class method that's overriden? (C++)

Question

I know some languages allow this. Is it possible in C++?

Answer 1

Yes, just specify the type of the base class.

For example:

#include 

struct Base
{
    void func() { std::cout << "Base::func\n"; }
};

struct Derived : public Base
{
    void func() { std::cout << "Derived::func\n"; Base::func(); }
};

int main()
{
    Derived d;
    d.func();
}