Is there a way to call an object's base class method that's overriden? (C++)

Question

I know some languages allow this. Is it possible in C++?

Answer 1

Yes:

#include 

class X
{
    public:
        void T()
        {
            std::cout << "1\n";
        }
};

class Y: public X
{
    public:
        void T()
        {
            std::cout << "2\n";
            X::T();             // Call base class.
        }
};


int main()
{
    Y   y;
    y.T();
}