Mysql table partition based on last digit of a column/id

Question

I want to create partitions based on last digit of employee id, i.e

all ids ending with 0 go to first partition,

ending with 1 go to seco         


        

Answer 1

I was wondering if there was a mod function allowed while creating a partition, I did it using

CREATE TABLE ti (id INT, amount DECIMAL(7,2))
ENGINE=INNODB
PARTITION BY HASH( MOD(id,10) )
PARTITIONS 10;

this created 10 partitions each id going in its partition ending with the same number as the last digit of the id

I added a few rows

    INSERT INTO ti VALUES (23123,343.22);
    INSERT INTO ti VALUES (23123,343.22);
    INSERT INTO ti VALUES (23144,343.22);
    INSERT INTO ti VALUES (23114,343.22);
    INSERT INTO ti VALUES (23124,343.22);
    INSERT INTO ti VALUES (23166,343.22);
    INSERT INTO ti VALUES (23116,343.22);
    INSERT INTO ti VALUES (23112,343.22);
    INSERT INTO ti VALUES (23199,343.22);

then tested it

 SELECT
  partition_name part,
  partition_expression expr,
  partition_description descr,
  table_rows
FROM
  INFORMATION_SCHEMA.partitions
WHERE
  TABLE_SCHEMA = SCHEMA()
  AND TABLE_NAME='ti';

OUTPUT:

part    expr    descr   table_rows
p0   MOD(id,10) \N  0
p1   MOD(id,10) \N  0
p2   MOD(id,10) \N  1
p3   MOD(id,10) \N  2
p4   MOD(id,10) \N  3
p5   MOD(id,10) \N  0
p6   MOD(id,10) \N  2
p7   MOD(id,10) \N  0
p8   MOD(id,10) \N  0
p9   MOD(id,10) \N  1

exactly what I wanted, thanks for pointing to the right link Incognito, but your answer was wrong, perhaps you misunderstood it