The aim is to show a form which will update the div on the page with the result
As far as I can see you now have:
but you still call $('#feditform').fadeIn('slow').ajaxForm(options);
as far as I can see and know about jQuery this will never show up, because the surrounding div is display:none
. I suggest to do three things:
hide()
and show()
, which will avoid trouble with some animations. If this works, you can go on and introduce the animated versions again.(document).ready
function via jQuery, so you can rely on those functions. We had bad experiences with 'mixed' approaches (hardcoded and via jQuery) especially concerning show and hide situations.$
. We tend to use the keyword jQuery
in those situations because this will always keep the scope.Hope this helps.