According to the docs for Array.prototype.slice() in JavaScript, the slice()
method returns a shallow copy of a portion of an array into a new array. It is my under
It's doing a shallow copy. But the values in that shallow copy point to the original arrays/objects, because they're object references.
So let's say we have:
var orig = [ [1] ];
In memory we have:
+−−−−−−−−−−−−−+ [orig:Ref22157]−−−−>| (array) | +−−−−−−−−−−−−−+ +−−−−−−−−−−−−−+ | 0: Ref84572 |−−−−−−−>| (array) | +−−−−−−−−−−−−−+ +−−−−−−−−−−−−−+ | 0: 1 | +−−−−−−−−−−−−−+
Now we do:
var copy = orig.slice();
and have:
+−−−−−−−−−−−−−+ [orig:Ref22157]−−−−>| (array) | +−−−−−−−−−−−−−+ | 0: Ref84572 |−−−+ +−−−−−−−−−−−−−+ | | | +−−−−−−−−−−−−−+ +−−−>| (array) | +−−−−−−−−−−−−−+ | +−−−−−−−−−−−−−+ [copy:Ref54682]−−−−>| (array) | | | 0: 1 | +−−−−−−−−−−−−−+ | +−−−−−−−−−−−−−+ | 0: Ref84572 |−−−+ +−−−−−−−−−−−−−+
Notice how the reference to the nested array (shown here notionally as "Ref84572" but we never see the real values of object references) has been copied, but still refers to the same nested array.
Here's proof it's shallow:
var orig = [ [1] ];
var copy = orig.slice();
console.log("orig[0][0] = " + orig[0][0]);
console.log("copy[0][0] = " + copy[0][0]);
console.log("Setting copy[0][0] to 2");
copy[0][0] = 2;
console.log("orig[0][0] = " + orig[0][0]);
console.log("copy[0][0] = " + copy[0][0]);
Notice that when we modify the state of the nested array, we see that modification no matter which route we take to getting to it (orig[0][0]
or copy[0][0]
).