memory corruption

Question

i was running a small c program:

#include
int main()
{
char *p;
p = (char *)malloc(10);
free(p);
free(p);
free(p);
printf(\"\\npointer is freed!!\         


        

Answer 1

It depend on the implementation of your OS (linux, windows...) who implement this function. Their behaviors may be different depending on the OS (undefined behavior), so you must not rely on them and you must free only one time all allocated memory in you program.

EDIT: it is not part of the OS but of the standard library which differ depending on the OS.