Step Number from 10 to N using python

Question

The Program must accept an integer N. The program must print all the stepping number from 10 to N, if there is no such number present the program should print -1 as

Answer 1

from itertools import product
from itertools import accumulate
import time

def main(n):
    result=set()
    for length in range(2,7):
        dxss=list(product([-1,1],repeat=length-1))
        for initial in range(1,10):
            for dxs in dxss:
                ans=list(accumulate(dxs,initial=initial))
                if all([(y in range(0,10)) for y in ans]):
                     result.add(int("".join(map(str,ans))))
    sorted_lst=sorted(result)
    return [x for x in sorted_lst if x

time=0.0020003318786621094[s]

[10,12,21,...989898]

Step number definition is "(nth digit - n-1th digit)= 1 or -1".

N is 10 < N < 10**7.Therefore, I must decide 1st number(1or2or..9) and 6 dx constructed by 1 or -1.